The value of given expression is 16
Solution:
Given expression is:
[tex]\sqrt{x^2} + \sqrt{x} \times \sqrt{x} + 6[/tex]
We have to find the value of expression when x = 5
Substitute x = 5
[tex]\sqrt{x^2} + \sqrt{x} \times \sqrt{x} + 6\\\\\sqrt{5^2} + (\sqrt{5} \times \sqrt{5}) + 6[/tex]
We know that,
[tex]\sqrt{a} \times \sqrt{a} = a[/tex]
Therefore, the above equation becomes,
[tex]\sqrt{5^2} + 5 + 6\\\\\sqrt{25} + 5 + 6\\\\5 + 5 + 6 = 10 + 6 = 16[/tex]
Thus the value of given expression is 16
