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Observe the reactions given below. Classify the reactants based on whether they are oxidized or reduced. Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s) 3Fe(s)+4H2O(g)→Fe2O3(s)+4H2(g) Drag the appropriate items to their respective bins. View Available Hint(s)

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Answer:

1. Zn is oxidize.

Cu is reduced.

2. Fe is oxidize.

H2 is reduced.

Explanation:

1. Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)

From the equation,

Zn changes oxidation number from 0 to +2. Therefore Zn is oxidized.

Cu2+ changes oxidation number from +2 to 0. Therefore, Cu2+ is reduced

2. 3Fe(s)+4H2O(g)→Fe2O3(s)+4H2(g)

From the equation,

Fe changes oxidation number from 0 to +3. Therefore, Fe is oxidized.

H changes oxidation number from +1 to 0. Therefore, H is reduced

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