Answer:
Correct answer: vₓ = 30V , i₀ = 5A
Explanation:
You first calculate the equivalent resistance of the parallel connection of two resistances of 12 and 6 ohms.
1/ Re₁ = 1/12 + 1/6 = (12 + 6) / (12 · 6) => 1/Re₁ = 18/72 => 1/Re₁ = 1/4 =>
Re₁ = 4Ω
then you calculate the equivalent resistance of a series connection of two resistances of 8 and Re₁ = 4Ω
Re₂ = Re₁ + 8 = 4 + 8 = 12Ω
then you calculate the electric current according to Oh's law
i₀ = vc / Re₂ = 60 / 12 = 5A
at the end you calculate the voltage drop vₓ on the resistor of 6Ω
vₓ = i₀ · 6Ω = 5A · 6Ω = 30V
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