Answer:
27.1806500378 V
Explanation:
k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]
q = Charge = [tex]1.6\times 10^{-19}\ C[/tex]
r = Distance = [tex]5.292\times 10^{-11}\ m[/tex]
Voltage is given by
[tex]V=k\dfrac{q}{r}\\\Rightarrow V=8.99\times 10^9\dfrac{1.6\times 10^{-19}}{5.292\times 10^{-11}}\\\Rightarrow V=27.1806500378\ V[/tex]
The potential difference is 27.1806500378 V
