Answer:
1st and 3rd figures have the same area
Step-by-step explanation:
1st figure is combined figure consisting of 4 m by 5 m rectangle and right triangle with legs
[tex]4-1=3\ m[/tex] and [tex]10-5=5\ m[/tex]
The area of the first figure is
[tex]A_{rectangle}=4\times 5=20\ m^2\\ \\A_{triangle }=\dfrac{1}{2}\cdot 3\cdot 5=7.5\ m^2\\ \\A_{1^{st}\ figure}=20+7.5=27.5\ m^2[/tex]
2nd figure is combined figure consisting of 3 m by 6 m rectangle and right triangle with legs
3 m and [tex]1+3+1=5\ m[/tex]
The area of the second figure is
[tex]A_{rectangle}=3\times 6=18\ m^2\\ \\A_{triangle }=\dfrac{1}{2}\cdot 3\cdot 5=7.5\ m^2\\ \\A_{2^{nd}\ figure}=18+7.5=25.5\ m^2[/tex]
3rd figure is combined figure consisting of 10 m by 2 m rectangle and right triangle with legs
3 m and [tex]10-5=5\ m[/tex]
The area of the third figure is
[tex]A_{rectangle}=2\times 10=20\ m^2\\ \\A_{triangle }=\dfrac{1}{2}\cdot 3\cdot 5=7.5\ m^2\\ \\A_{3^{rd}\ figure}=20+7.5=27.5\ m^2[/tex]
