The toasters produced by a company have a normally distributed life span with a mean of 5.8 years and a standard deviation of 0.9 years, what warranty should be provided so that the company is replacing at most 10% of their toasters sold? a. 4.3 years b. 5.9 years c. 4.5 years d. 4.6 years

Respuesta :

Answer:

d. 4.6 years

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 5.8, \sigma = 0.9[/tex]

What warranty should be provided so that the company is replacing at most 10% of their toasters sold?

Only those on the 10th percentile or lower will be replaced.

So the warranty is the value of X when Z has a pvalue of 0.10.

So it is X when [tex]Z = -1.28[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 5.8}{0.9}[/tex]

[tex]X - 5.8 = -1.28*0.9[/tex]

[tex]X = 4.6[/tex]

So the correct answer is:

d. 4.6 years