Given the unbalanced equation: N2(g) + H2(g) → NH3(g)
When the equation is balanced using the smallest whole-number coefficients, the ratio of moles of hydrogen consumed to moles of ammonia produced is
1 ) 1:3
2) 2:3
3) 3:1
4) 3:2

There are 2 nitrogen atoms on left hand side and 1 nitrogen atoms on right hand site therefore, to balance them multiply NH₃ on right hand side by 2 i.e.

N₂ + H₂ → 2 NH₃

Step 3: Balance Hydrogen Atoms;

Now, there are 2 hydrogen atoms on left hand side and 6 hydrogen atom on right hand site therefore, to balance them multiply H₂ on left hand side by 3 i.e.

N₂ + 3 H₂ → 2 NH₃

Now, the equation is balanced.

Step 4: Finding out mole ratios:

From balanced chemical equation it can be concluded that 3 moles of H₂ are involved in producing 2 moles of NH₃ hence, the mole ratio of consumption of H₂ to production of NH₃ is 3:2.

yminose731 yminose731 · Answer 2 · 2021-01-26T21:22:58+01:00

yminose731 yminose731

26-01-2021

Answer:

4) 3:2

Explanation:

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Given the unbalanced equation: N2(g) + H2(g) → NH3(g) When the equation is balanced using the smallest whole-number coefficients, the ratio of moles of hydrogen consumed to moles of ammonia produced is 1 ) 1:3 2) 2:3 3) 3:1 4) 3:2

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Given the unbalanced equation: N2(g) + H2(g) → NH3(g)
When the equation is balanced using the smallest whole-number coefficients, the ratio of moles of hydrogen consumed to moles of ammonia produced is
1 ) 1:3
2) 2:3
3) 3:1
4) 3:2