Answer:
The answer to this is the concentration of glucose (C6H12O6) in mg/dL = 95.48 mg/dL
Explanation:
To solve this we list out the known variables thus
Measured concentration of glucose (C6H12O6) = 5.3mM per liter
The molar mass of glucose = 180.156 g/mol
From the above, it is seen that one mole of glucose contains 180.156 grams of C6H12O6 therefore 5.3 mM which is 5.3 × 10⁻³ moles contains
5.3 × 10⁻³ moles × 180.156 g/mol = 0.9548 grams of glucose
Also 1 d L = 0.1 L or 1 L = 10 dL and 1 mg = 1000 g, hence
thus 0.9548 grams per liter is equivalent to 1000/10 × 0.9548 milligrams per dL or 95.48 mg/dL
