Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parrots, he has 4 coins left. Or, if he splits all of his coins into 11 equal piles for his shipmates, he has 4 coins left. Assuming every pile has at least 1 coin, what is the least possible number of coins Pirate Jack has?

Respuesta :

The least possible number of coins Pirate Jack has, is 81 coins.

Step-by-step explanation:

Given,

When the coins are divided into 7 equal piles, 4 coins are left.

When the coins are divided into 11 equal piles, 4 coins are left.

We will take LCM of both 7 and 11.

7 = 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, ....

11 = 11, 22, 33, 44, 55, 66, 77, 88, ...

The least common multiple of 7 and 11 is 77.

As 4 coins are left, therefore, we will add those coins.

Total possible coins = 77+4 = 81

The least possible number of coins Pirate Jack has, is 81 coins.

Keywords: LCM, addition

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