The end voltage is 9.01 volts.
Explanation:
The emf of the battery is 12 volts.
The resistance of the circuit = 1.75 ohms.
The resistance of the applicant attached = 5.5 ohms.
So, total resistance of the circuit = [tex]1.75 + 5.5[/tex] ohms = 7.25 ohms.
According to the equation, the voltage applied is equal to the product of the current and the resistance.
V=iR.
So, 12 = [tex]i \times7.25[/tex].
So, i = 1.66.
Therefore, the voltage at the end of the circuit = [tex]12 - 1.66\times1.75[/tex]volts
= 9.01volts.
So the end voltage is 9.01 volts.
