The electrostatic force between the two charges is [tex]3.4\cdot 10^{-8}N[/tex]
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges
r is the separation between the two charges
In this problem, we have the following data:
[tex]q_1 = q_2 = 1.00e[/tex] is the magnitude of the two charges, where
[tex]e=1.6\cdot 10^{-19}C[/tex] is the fundamental charge
[tex]r=8.19\cdot 10^{-11}m[/tex] is the separation between the two charges
Substutiting into the equation, we find the force:
[tex]F=(8.99\cdot 10^9)\frac{(1.00\cdot 1.6\cdot 10^{-19})^2}{(8.19\cdot 10^{-11})^2}=3.4\cdot 10^{-8}N[/tex]
Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
