The value of B = [tex]\dfrac{2S-NA}{N}[/tex]
Step-by-step explanation:
The given equation,
[tex]S=\dfrac{N}{2}(A+B)[/tex]
To find, the value of B in terms of S, N and A = ?
∴ [tex]S=\dfrac{N}{2}(A+B)[/tex]
By crossmultiplication, we get
⇒ N(A + B) = 2S
⇒ NA + NB = 2S
⇒ NB = 2S - NA
⇒ B = [tex]\dfrac{2S-NA}{N}[/tex]
∴ The value of B = [tex]\dfrac{2S-NA}{N}[/tex]