.92 moles of carbon dioxide, CO2, was produced when you burned C6H120. (glucose) with O2.
How many grams of water was also produced?
CGH 120(s) + 6 O2(g) – 6 CO2 (g) + 6 H20 (8)
O moles to moles
moles to mass
mass to moles
mass to mass

You need to compare the number of coefficient of the reaction product to find how much water produced. The reaction formula will produce 6 carbon dioxide(CO2) and 6 water (H2O).

If the reaction produces 0.92 moles of carbon dioxide, then the amount of water produced in moles will be: 0.92 moles * (6/6)= 0.92 moles

The molar mass of water is 18g/mol, so the calculation of moles to mass will be: 0.92 moles * (18g/mol)= 16.56g.

.92 moles of carbon dioxide, CO2, was produced when you burned C6H120. (glucose) with O2. How many grams of water was also produced? CGH 120(s) + 6 O2(g) – 6 CO2 (g) + 6 H20 (8) O moles to moles moles to mass mass to moles mass to mass

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.92 moles of carbon dioxide, CO2, was produced when you burned C6H120. (glucose) with O2.
How many grams of water was also produced?
CGH 120(s) + 6 O2(g) – 6 CO2 (g) + 6 H20 (8)
O moles to moles
moles to mass
mass to moles
mass to mass