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Given this equation: 3 MgCl2 + 2 AL - 3 Mg + 2 AlCl3, if 278 grams of magnesium chloride
reacted how many grams of aluminum chloride are produced?
O mass to mass
moles to mass
mass to moles
moles to moles
D
Question 3
5 pts

Respuesta :

Answer: m= 1.02x10² g AlCl3 or 1091.3 g AlCl3

Explanation: solution attached.

Convert mass of Mg to moles

Do the mole ratio between Mg and AlCl3 based from the balanced equation.

Convert moles of AlCl3 to mass using its molar mass.

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