Respuesta :
Answer:
In conclussion, 0.60 moles of HCOOH contains the greatest mass of O
Explanation:
Let's make some rules of three, to solve this problem:
1 mol of ethanol has 2 moles of C, 6 moles of H, and 1 mol of oxygen
Therefore, 0.75 moles of ethanol must have 0.75 mol of oyxgen
Let's convert the moles to mass → 0.75 mol . 16 g/ 1 mol = 12 g
1 mol of formic acid has 2 moles of H, 1 mol of C and 2 mol of oxygen
0.60 moles of formic acid must have (0.6 .2) / 1 = 1.2 mol of O
If we convert the amount to mass → 1.2 mol . 16 g/ 1mol = 19.2 g
1 mol of water has 1 mol of oyxgen
Therefore, we have 1 mol of oxygen with a mass of 16 g.
In conclussion, 0.60 moles of HCOOH contains the greatest mass of O
Answer:
0.60 mole of formic acid contains the greatest mass of oxygen
(19.2 grams)
Explanation:
Step 1: Data given
Moles of ethanol = 0.75 moles
Molar mass ethanol = 46.07 g/mol
Moles of formic acid = 0.60 moles
Molar mass of formic acid = 46.03 g/mol
Moles of H2O = 1.0
Molar mass of H2O = 18.02 g/mol
Step 2: Calculate moles of oxygen in each
Ethanol: For 1 mol ethanol we have 1 mol oxygen
For 0.75 moles ethanol we have 0.75 moles O
Mass O = 0.75 moles * 16.0 g/mol = 12.0 grams O
Formic acid: For 1 mol formic acid, we have 2 moles O
For 0.60 moles formic acid, we have 2*0.60 = 1.20 moles O
Mass O = 1.20 moles * 16.0 g/mol = 19.2 grams O
H2O: for 1.0 mol H2O we have 1 mol O
Mass O = 18.02 g/mol * 1.0 mol = 18.02 grams
0.60 mole of formic acid contains the greatest mass of oxygen
(19.2 grams)
