Answer:
The length of the rectangle is 70 cm
The width of the rectangle is 32 cm
Step-by-step explanation:
Given:
perimeter of the rectangle = 204 feet
Its length is six feet longer that twice its width
To Find:
The dimensions of the rectangle = ?
Solution:
Let the width of the rectangle be x
Then its length is six feet longer that twice its width.
That is length = 6 + 2x
Now we know that the perimeter of the rectangle is
perimeter = 2(length + width)
204 = 2(6+2x+x)
204 = 2(6+3x)
204 = 12 +6x
204 - 12 = 6x
192 = 6x
x =[tex]\frac{192}{6}[/tex]
x = 32
Thus the width is 32 cm
Its length is
=6 + 2x
=6 + 2(32)
=6 + 64
= 70 cm
