Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-4, -2), B(-2, -2), C(-2, 7)C(−2,7)C, D(-4, 7
What is the area of rectangle ABCD?

Respuesta :

Answer:

The area of rectangle ABCD is [tex]18\ units^2[/tex]

Step-by-step explanation:

Plot the figure to better understand the problem

we have the vertices

A(-4, -2), B(-2, -2), C(-2, 7), D(-4, 7)

see the  attached figure

The area of the rectangle is equal to

[tex]A=LW[/tex]

where

L is the length

W is the width

In this problem we have

[tex]L=BC=7-(-2)=9\ units[/tex] ---> difference of the y-coordinates

[tex]W=AB=-2-(-4)=2\ units[/tex] ---> difference of the x-coordinates

substitute

[tex]A=(9)(2)=18\ units^2[/tex]

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