Answer:
0.2637
Step-by-step explanation:
We see from the question that the 5-card hand contains all 4 suits as shown below;
Number of cards = 52
Number of suits = 4
For the favorable cases therefore, we will choose two cards from the suit in which two cards are drawn. Then we will proceed to choose one card from each of the other suits.
4 suits will divide into 52 cards to give = (52 / 4) = 13 cards
Hence, the required probability;
[tex]= {\frac{4 *13c_2*13c_1*13c_1*13c_1}{52c_5}}\\= {\frac{2197}{8330}}\\= 0.2637[/tex]
