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A line has a slope of Negative three-fourths and passes through the point (–5, 4). Which is the equation of the line?
y = negative three-fourths x + one-fourth
y = negative three-fourths x + 4
y = negative three-fourths x minus 2
y = negative three-fourths x minus one-fourth

Respuesta :

The equation of the line is [tex]y=-\frac{3}{4}x+\frac{1}{4}[/tex]

Step-by-step explanation:

The equation of a line can be written using the following form

[tex]y-y_0 = m(x-x_0)[/tex]

where

m is the slope of the line

[tex](x_0,y_0)[/tex] are the coordinates of a point lying on the line

For the line in this problem, we know that:

[tex]m=-\frac{3}{4}[/tex] is the slope

[tex](x_0,y_0)=(-5,4)[/tex] are the coordinates of the point

Therefore, substituting into the equation,

[tex]y-4=-\frac{3}{4}(x-(-5))[/tex]

And re-arranging the equation we get:

[tex]y-4=-\frac{3}{4}(x+5)\\y-4=-\frac{3}{4}x-\frac{15}{4}\\y=-\frac{3}{4}x+(4-\frac{15}{4})\\y=-\frac{3}{4}x+\frac{1}{4}[/tex]

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Answer:

The equation of the line is y=-3/4x+1/4

Step-by-step explanation:

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