Respuesta :
Answer:
(a). The mass of the block of ice is 62.8 kg.
(b). The distance is 24.192 m.
Explanation:
Given that,
Horizontal force = 80.5 N
Distance = 13.0 m
Time = 4.50 s
(a). We need to calculate the acceleration of the block of ice
Using equation of motion
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Put the value into the formula
[tex]13=0+\dfrac{1}{2}\times a\times(4.50)^2[/tex]
[tex]a=\dfrac{13\times2}{(4.50)^2}[/tex]
[tex]a=1.28\ m/s^2[/tex]
We need to calculate the mass of the block of ice
Using formula of force
[tex]F = ma[/tex]
[tex]m=\dfrac{F}{a}[/tex]
Put the value into the formula
[tex]m=\dfrac{80.5}{1.28}[/tex]
[tex]m=62.8\ kg[/tex]
(b). If the worker stops pushing at the end of 4.50 s,
We need to calculate the velocity
Using equation of motion
[tex]v =u+at[/tex]
Put the value into the formula
[tex]v=0+1.28\times4.50[/tex]
[tex]v=5.76\ m/s[/tex]
We need to calculate the distance
Using formula of distance
[tex]v = \dfrac{d}{t}[/tex]
[tex]d=v\times t[/tex]
Put the value into the formula
[tex]d=5.76\times4.20[/tex]
[tex]d=24.192\ m[/tex]
Hence, (a). The mass of the block of ice is 62.8 kg.
(b). The distance is 24.192 m.
