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A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. What is the volume of the balloon at this depth? a. 0.154 L b. 6.50 L c. 0.615 L d. 1.63 L d. None of the above

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anfabba15

Answer:

Option a . 0.154L

Explanation:

P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

Cricetus

"0.154 L" is the volume of the balloon.

Given:

Pressure,

  • [tex]P_1 = 1 \ atm[/tex]
  • [tex]P_2 = 3.25 \ atm[/tex]

Volume,

  • [tex]V_1 = 0.5 \ L[/tex]
  • [tex]V_2 = ?[/tex]

As we know,

→ [tex]P_1. V_1 = P_2 .V_2[/tex]

or,

→      [tex]V_2 = \frac{P_1. V_1}{P_1}[/tex]

By substituting the values, we get

            [tex]= \frac{0.5\times 1}{3.25}[/tex]

            [tex]= \frac{0.5}{3.25}[/tex]

            [tex]= 0.154 \ L[/tex]

Thus the above answer i.e., "option a" is correct.

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