Answer:
12
12
24
Explanation:
Musca domestica is the scientific name of an animal popularly known as Housefly. From the question, it is known that this organism has a haploid chromosome number of 6.
In a diploid chromosomes, the number of chromatids that will be present will be twice of that in haploid.
Since haploid (n) = 6, diploid (2n) will be; 2 × 6 = 12
Somatic cells on the other hand also exhibit diploid number of chromosomes, again it means we will have (2n) = 2 × 6 = 12
In metaphase cell, cells do make sure they complete the S'phase of the cell cycle before cellular division.Therefore, the DNA present in the chromatids in the S'phase actively engage in chromatids doubling, as a result, 24 chromatids (i.e 12 × 2= 24) exists in the metaphase cell.
The chromatids should be present in a diploid, somatic, metaphase cell-
The scientific name of the fly Housefly is Musca domestica. It is known that this organism has a haploid chromosome number of 6. In the diploid cells, the number of chromatids that will be present will be twice that in haploid.
Diploid genome (2n)
= [tex]2\times6=12[/tex].
Somatic cells also exhibit diploidy (2n)
= 12
Metaphase stage cells contain 24 chromatids as cells before entering cell division complete S-phase of the cell cycle in which DNA present in chromatids become double due to replication.
Learn more about Metaphase:
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