1. [tex]\frac{x^3}{x^8}=x^{-5}[/tex]
2. [tex]\frac{6x}{2x^8} = 3x^{-7}[/tex]
3. [tex]\frac{28x^6}{21x^2} = \frac{4}{3}x^4[/tex]
Step-by-step explanation:
1. x^3/x^8
Given fraction is:
[tex]\frac{x^3}{x^8}[/tex]
When the bases are same in both numerator and denominator then the exponents can be added
i.e.
[tex]\frac{x^a}{x^b} = x^{a-b}[/tex]
So,
[tex]\frac{x^3}{x^8} = x^{3-8} = x^{-5}[/tex]
Part b:
[tex]\frac{6x}{2x^8}\\= \frac{3.2.x}{2.x^8}\\=\frac{3x}{x^8}\\=3x{1-8}\\=3x^{-7}[/tex]
Part c:
Given
[tex]\frac{28x^6}{21x^2}\\= \frac{7.4.x^6}{7.3.x^2}\\=\frac{4}{3} x^{6-2}\\=\frac{4}{3}x^4[/tex]
Keywords: Fractions, exponents
Learn more about fractions at:
- brainly.com/question/5282516
- brainly.com/question/5424148
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