Respuesta :

Chelboy

Answer:12.28m/s

Explanation:

momentum of baseball =mass of baseball x velocity of baseball

Momentum of baseball =0.31x21

Momentum of baseball =6.51kgm/s

For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball

6.51=0.53 x velocity of softball

Velocity of softball =6.51/0.53

Velocity of softball =12.28m/s

onyebuchinnaji

The velocity of the softball that must be equal to the momentum of the baseball is 12.28 m/s.

The given parameters;

  • mass of the soft ball, m₁ = 0.53 kg
  • mass of the baseball, m₂ = 0.31 kg
  • velocity of the baseball, u₂ = 21 m/s

Apply the principle of conservation of linear momentum to determine the velocity of the softball;

[tex]m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.31 \times 21}{0.53} \\\\u_1 = 12.28 \ m/s[/tex]

Thus, the velocity of the softball that must be equal to the momentum of the baseball is 12.28 m/s.

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