Answer:
[tex]q = 2.17\times 10^{-15}~{\rm C}[/tex]
Explanation:
The relation between the acceleration and the electrical force between the spheres can be found by Newton's Second Law.
[tex]\vec{F} = m\vec{a}\\\vec{F} = (1.4\times 10^{-3})(110) = 0.154~N[/tex]
This is equal to the Coulomb's Force.
[tex]F = \frac{1}{4\pi\epsilon_0}\frac{q_1 q_2}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{2q}{(1.6 \times 10^{-2})^2} = 0.154\\q = 2.17\times 10^{-15}~C[/tex]
