Answer:
a) 0.06
b) 0.3
c) 0.44
Step-by-step explanation:
We are given the following in the question:
A and B are two independent events.
P(A) = 0.3
P(B) = 0.2
a) P(A intersect B)
[tex]P(A\cap B) = P(A)\times P(B) = 0.3\times 0.2 = 0.06[/tex]
b) P(A|B)
[tex]P(A|B) = \dfrac{P(A\cap B)}{P(B)} = \dfrac{0.06}{0.2} = 0.3[/tex]
c) P(A union B)
[tex]P(A\cup B) = P(A) + P(B) - P(A\cap B)\\P(A\cup B) = 0.3 + 0.2 - 0.06 = 0.44[/tex]
