Answer:
f₂ = 0.019 m
Explanation:
Let's analyze this exercise a bit, when taking a picture the image should always be in the same place, position of the CCD, let's use the builder's equation to find this distance from the image (i)
1 / f = 1 / o + 1 / i
Where f is the focal length and "o, i" are the distances to the object and image, respectively
1 / i = 1 / f - 1 / o
Let's reduce the magnitudes to the SI system
f = 50 mm = 0.050 m
o = 5.0 m
Let's calculate
1 / i = 1 / 0.050 - 1 / 5.0 = 20- 0.2 = 19.8
i = 0.020 m
Now the object is 60 cm, rotates the lens and has a new focal length
o₂ = 60 cm = 0.60 m
1 / f = 1 / 0.60 + 1 / 0.020 = 1.66 + 50 = 51.66
f₂ = 0.019 m
