Julia has 2 children who are 4 years apart in age. Julia is four times older than her youngest child. The sum of the ages of Julia and her 2 kids is 76 years

Respuesta :

Answer: Julia is 48 years

The oldest child is 16 years

The youngest child is 12 years

Step-by-step explanation:

Let x represent the age of the youngest child.

Let y represent the age of the oldest child.

Let x represent Julia's age.

The sum of the ages of Julia and her 2 kids is 76 years. This means that

x + y + z = 76- - - - - - - - - - -1

Julia has 2 children who are 4 years apart in age. This means that

y = x + 4

Julia is four times older than her youngest child. This means that

z = 4x

Substituting z = 4x and y = x + 4 into equation 1, it becomes

x + x + 4 + 4x = 76

6x = 76 - 4 = 72

x = 72/6 = 12

y = x + 4 = 12 + 4

y = 16

z = 4x = 4 × 12

z = 48

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Answer:

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Step-by-step explanation: