Answer: The molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
n = moles of solute
[tex]V_s[/tex] =volume of solution in ml
Given : 26.0 g of phosphoric acid in 100 g of solution.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{26.0g}{98g/mol}=0.265moles[/tex]
Volume of solution =[tex]\frac{\text {Mass of solution}}{\text {Density of solution}}=\frac{100g}{1.155g/ml}=86.6ml[/tex]
[tex]Molarity=\frac{0.265\times 1000}{86.6ml}=3.06M[/tex]
Molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M
