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bhuvna789456

68 is the 22nd term of the following sequence.

Step-by-step explanation:

  • The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the  Arithmetic progression ( AP).
  • For finding the nth term in the AP we have a formula tn = a + (n-1) × d
  • Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
  • Thus here tn = 5 + ( 22 - 1 ) × 3.
  • On subtracting we get tn = 5 + (21 ) × 3
  • On multiplying we get tn = 5 + 63
  • After adding we get tn = 68. It is the 22nd term in the given series.
Lanuel

the twenty second (22) term of the sequence 5, 8, 11, ...... is: D. 68.

Given the following data:

  • First (1st) term = 5
  • Second term = 8
  • Third term = 11

To find the twenty second (22) term of the sequence:

Mathematically, the [tex]n^{th}[/tex] term of a sequence is calculated by using the following formula;

[tex]a_n = a + (n - 1)d[/tex]

Where:

  • a is the first term.
  • n is the term number.
  • d is the common difference.

First of all, we would determine the common difference.

[tex]d = 2^{nd} \; term - 1^{st}\;term\\\\d = 8 - 5 \\\\d = 3[/tex]

Substituting the given parameters into the formula, we have;

[tex]a_{22} = 5 + (22 - 1)3\\\\a_{22} = 5 + (21)3\\\\a_{22} = 5 + 63\\\\a_{22} = 68[/tex]

Therefore, the twenty second (22) term of the sequence is 68.

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