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From the choices provided below, list the reagent(s) in order that will react with 3-pentanone to form 3-phenyl-2-pentene. (List your answer as a letter (single-step transformation), or series of letters (multi-step transformation) in the order the reagents are used, with no commas separating them. No more than four steps are required for this synthesis.)a. H2 / Pt e. 1. PhMgBr 2. H3O+b. H2SO4, Δ f. H3O+c. OsO4, H2O2 g. RCO3Hd. 1. ch3mgbr2. h30+ h. KOH

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Answer:

The reagents will be as follows:

g.

h.

c.

e

Explanation:

The reaction of ketones requires a reaction with methymagnesium iodide. The reaction mechanism follows this pattern:

aldehyde + iodide reagent → methylpentanol

This induces a stereogenic centre in the organic molecule. In this case, the ketone does not yield a chiral alochol.

The bromide group in the reagant influences the splting of the double C=O bond in the side chain to from 3 - phenyl - 2- pentene

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