The following data represent the social ambivalence scores for 15 people as measured by a psychological test. (The higher the score, the stronger the ambivalence.) 8 12 11 15 14 10 8 3 8 7 21 12 9 19 11 (a) Guess the value of s using the range approximation. s ≈ (b) Calculate x for the 15 social ambivalence scores. Calculate s for the 15 social ambivalence scores. (c) What fraction of the scores actually lie in the interval x ± 2s? (Round your answer to two decimal places.).

Respuesta :

Answer:

a) 4.5

b) x = 11.2, s = 4.65

c) 93.33%                                                

Step-by-step explanation:

We are given he following data in the question:

8, 12, 11, 15, 14, 10, 8, 3, 8, 7, 21, 12, 9, 19, 11

a) Estimation of standard deviation using range

Sorted data: 3, 7, 8, 8, 8, 9, 10, 11, 11, 12, 12, 14, 15, 19, 21

Range = Maximum - Minimum = 21 - 3 = 18

Range rule thumb:

  • It states that the range is 4 times the standard deviation for a given data.

[tex]s = \dfrac{\text{Range}}{4} = \dfrac{18}{4} = 4.5[/tex]

b) Mean and standard deviation

Formula:

[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]  

where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.  

[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]

[tex]Mean =\displaystyle\frac{168}{15} = 11.2[/tex]

Sum of squares of differences = 302.4

[tex]S.D = \sqrt{\dfrac{302.4}{14}} = 4.65[/tex]

c)  fraction of the scores actually lie in the interval x ± 2s

[tex]x \pm 2s = 11.2 \pm 2(4.65) = (1.9,20.5)[/tex]

Since 14 out of 15 entries lie in this range, we can calculate the percentage as,

[tex]\dfrac{14}{15}\times 100\% = 93.33\%[/tex]