Answer:
(3) 690 N
Explanation:
Force: This is the product of mass and acceleration of a body. The S.I unit of force is Newton(N).
The formula for force is given as,
F = ma..................... Equation 1
Where F = force, m = mass, a = acceleration.
Also,
a = (v-u)/t................... Equation 2
Where v = Final velocity, u = initial velocity, t = time.
Given: u = 6.0 m/s, v = 0 m/s (bring to stop), t = 0.65 s.
Substitute into equation 2
a = (0-6)/0.65
a = -6/0.65
a = -9.23 m/s²
Also given: m = 75 kg
Substitute again into equation 1
F = 75(-9.23)
F = -692.25 N
The negative sign tells that the force oppose the motion of the player
F ≈ 690 N
Hence the right option is (3) 690 N
The magnitude of the average force required to stop the player in 0.65 second is 690 N. And option (3) is correct.
Given data:
The mass of hockey player is, m = 75 kg.
The speed of hockey player is, v = 6.0 m/s.
The reaction time is, t = 0.65.
Use the concept of impulse - momentum theorem to obtain the value of average force acting on the hockey player as,
As per the impulse - momentum theorem,
[tex]F = \dfrac{mv}{t}[/tex]
Here, F is the average force exerted on the hockey player.
Solving as,
[tex]F = \dfrac{75 \times 6}{0.65 }\\\\F \approx 690 \;\rm N[/tex]
Thus, the magnitude of the average force required to stop the player in 0.65 second is 690 N. And option (3) is correct.
Learn more about the impulse - momentum theorem here:
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