Answer:
None of the exponential equations given in the two options have initial value 2.
Step-by-step explanation:
The general form of an exponential function to have initial value of 2 is
[tex]f(x) = 2(b)^{x}[/tex] where b ≠ 1.
Now, in the given two options the first one has equation [tex]f(x) = 3(2)^{x}[/tex], and the other given table forms the exponential function equation [tex]f(x) = \frac{1}{2}(2)^{x}[/tex].
Therefore, none of the exponential equations given in the two options have initial value 2. (Answer)
