which function has a simplified base of 4^3√4?

Answer:
The function is [tex]f(x) = 4(\sqrt[3]{16} )^{2x}[/tex].
Step-by-step explanation:
We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).
Now, the exponential function in the option III will be the answer.
The function is [tex]f(x) = 4(\sqrt[3]{16} )^{2x}[/tex].
So, the base is [tex](\sqrt[3]{16} )^{2}[/tex] = [tex]\sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}[/tex]. (Answer)
The general formula of an exponential function is [tex]f(x) = a(b)^{x}[/tex] , where b is called the base of the function.
The function that has a simplified base of (4∛4) is;
Option C; 4(∛16)^(2x)
From the general formula of an exponential function, we know that;
f(x) = a(b)^(x)
Now, we have;
f(x) = (4∛4)^(x)
Thus, looking at the options, option C is correct because;
In 4(∛16)^(2x), the base is (∛16)² and when we simplify it, we will get 4³(√4) because;
(∛16)² = √(16^(⅔))
>> 256^(⅓)
>> 4∛4
This is the same as our initial value.
Read more about exponential functions at; https://brainly.com/question/13917934