Answer:
Charge enter a 0.100 mm length of the axon is [tex]8.98\times 10^{-12} C[/tex]
Explanation:
Electric field E at a point due to a point charge is given by
[tex]E=k \frac{q}{r^2}[/tex]
where [tex]k[/tex] is the constant =[tex]9.0 \times 10^9 Nm^2 / C^2[/tex]
[tex]q[/tex] is the magnitude of point charge and [tex]r[/tex] is the distance from the point charge
Charges entering one meter of axon is [tex]5.\times 10^{11} \times (+e)[/tex]
Charges entering 0.100 mm of axon is [tex]5.\times 10^{11} \times (+e) \times (0.1 \times 10^{-3}[/tex]
substituting the value of [tex]+e=1.6\times 10^{-19} C[/tex] in above equation, we get charge enter a 0.100 mm length of the axon is
[tex]q=5.\times 10^{11} \times1.6\times 10^{-19} \times (0.1 \times 10^{-3}\\q=8.98\times 10^{-12} C[/tex]
