Answer:
The person with locked legs will experience greater impact force.
Explanation:
Let the two persons be of nearly equal mass (say m)
The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,
[tex]v=\sqrt{2gH}[/tex]
([tex]g[/tex] = acceleration due to gravity)
which can be derived from Newton's equation of motion,
[tex]v^2=u^2+2aS[/tex]
Now, the time taken (say [tex]t[/tex] ) for the momentum ( [tex]mv[/tex] ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.
We know that,
[tex]Force=\frac{\Delta(mv)}{t}[/tex]
Naturally, the person who bends his legs will experience lesser force since [tex]t[/tex] is larger.
