A gas is contained in a thick-walled
balloon. When the pressure changes
from 18.7 psi to 20.2 psi, the volume
changes from 0.475 L to 1.054 L and
the temperature changes from
K to 465 K.

Respuesta :

Answer:

                   T₁  =  194 K

Solution:

Data Given:

                 Initial Temperature  =  T₁  =  ??

                 Final Temperature  =  T₂  =  465 K

                 Initial Pressure  =  P₁  =  18.7 psi

                 Final Pressure  =  P₂  =  20.2 psi

                 Initial Volume  =  V₁  =  0.475 L

                 Final Volume  =  V₂  =  1.054 L

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹,

Taking number of moles and R constant we can have following formula for initial and final states,

                P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for T₁,

                T₁  =  P₁ V₁ T₂ / P₂ V₂

Putting values,

                T₁  =  (18.7 psi × 0.475 L × 465 K) / (20.2 psi × 1.054 L)

               T₁  =  194 K

Answer:

194 K

Explanation: