[tex]\text{ The vertex of } y = 4x^2 - 2 \text{ is (h, k) = (0, -2)}[/tex]
Solution:
Given that we have to find the vertex
The vertex form of equation is written as:
[tex]y = a(x-h)^2+k[/tex]
Where, (h, k) is the vertex
Given equation is:
[tex]y = 4x^2 - 2[/tex]
Convert to vertex form
[tex]y = 4x^2 -2\\\\x^2\ can\ be\ written\ as\ (x+0)^2\\\\Thus\ above\ equation\ becomes\\\\y = 4(x+0)^2 - 2[/tex]
The above equation is of vertex form
On comparing vertex form with above equation,
[tex]y = a(x-h)^2+k\\\\y = 4(x+0)^2 -2[/tex]
On comparing we get,
h = 0
k = -2
Thus vertex is (h, k) = (0, -2)
