Answer:
[tex]y=-9[/tex]
Step-by-step explanation:
Given:
System of equations:
[tex]\frac{1}{5}x-\frac{1}{3}y=-1[/tex]
[tex]-\frac{3}{4}x+\frac{1}{3}y=12[/tex]
The equations were multiplied by constants and added together to determine that the value of [tex]x[/tex] which = -20
To find the value of [tex]y[/tex].
Solution
In order to find out the value of [tex]y[/tex] in any of the equations, we will plugin the value of [tex]x[/tex] which was found out bu solving the system of equations.
Plugging in [tex]x=-20[/tex] in first equation.
[tex]\frac{1}{5}(-20)-\frac{1}{3}y=-1[/tex]
Solving for [tex]y[/tex]
[tex]-4-\frac{1}{3}y=-1[/tex]
Adding 4 both sides.
[tex]-4+4-\frac{1}{3}y=-1+4[/tex]
[tex]-\frac{1}{3}y=3[/tex]
Multiplying both sides by -3.
[tex](-3)-\frac{1}{3}y=3\times (-3)[/tex]
∴ [tex]y=-9[/tex] (Answer)
