Angular velocity: 31.9 rpm
Explanation:
The centripetal acceleration of an object in circular motion is given by
[tex]a=\omega^2 r[/tex]
where
[tex]\omega[/tex] is the angular velocity
r is the radius of the circle
For the ball in this problem, we have:
r = 0.88 m is the radius of the circle
The centripetal acceleration is
[tex]a=g=9.81 m/s^2[/tex]
Therefore, the angular velocity must be
[tex]\omega=\sqrt{\frac{a}{r}}=\sqrt{\frac{9.8}{0.88}}=3.34 rad/s[/tex]
And then since we have
[tex]1 rev = 2 \pi rad\\1 min = 60 s[/tex]
We can convert into revolutions per minute:
[tex]\omega = 3.34 rad/s \cdot \frac{60 s/min}{2\pi rad/rev}=31.9 rpm[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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