Answer:
[tex]\frac{(2a+1)^{2} }{50a}[/tex]
Step-by-step explanation:
[tex]\frac{2a+1}{10a-5} * \frac{4a^{2} - 1}{10a}\\ = \frac{2a+1}{5(2a-1)} * \frac{(2a+1)(2a-1)}{10a}\\=\frac{(2a+1)^{2} }{50a}[/tex]
1.The expression given is in division so when changing to multiplication the fraction is reversed.
2.Using algebra identity [tex]a^{2} - b^{2} = (a+b)(a-b)[/tex].
3. Taking the common factor 5 out.
4. Finally cancelling the like terms from the numerator and denominator.
