Bob is color blind, but he knows that neither of his parents were color blind. He is wondering if he received the gene for color blindness from his mother l, his father, or both of his parents. What would you tell Bob Show a Punnett square to prove your answer!

Explanation: Colour blindness is a disorder in which a person is unable to distinguish certain colours such as green and blue. Colour blindness is an X-linked (sex-linked) disorder, which means that colour blindness are carried on the X chromosome. Males are usually the sufferers because they have only one X chromosome which once affected will result in colour blindness while females are usually the carriers because they normally have two X chromosome and hardly do they have the two chromosomes affected except if the person is from a mother who is a carrier and a father who is a sufferer.

Bob's parents are likely to have one female with normal vision XBXB, one female who is heterozygous for colour blindness (a carrier) XBXb, a male with normal vision XBY and another male who is colourblind XbY.

See the attached punnet square.

marianaegarciaperedo marianaegarciaperedo · Answer 2 · 2022-01-21T12:46:58+01:00

Color-blindness is an X-linked recessive condition. Bob received the gene for color blindness from his mother.

Color-blindness is a disfunction characterized by an alteration in color perception.

This alteration might affect perception from only partial confusion and difficulties in distinguishing some tones of green and red, up to no chromatic distinction.

Color-blindness is an X-linked condition.

→ Women that are h0m0zygous recessive will be completely color-blinded (X⁺X⁺), and the heter0zyg0us woman has partial color-blindness (X⁺X⁻).

→ Men, instead, are or are not color-blinded (X⁺Y or X⁻Y).

In the exposed example, let us say that

Color-blindness is the recessive trait → X⁻

Normal sight is the dominant trait → X ⁺

X⁻ represents the X chromosome carrying the recessive allele.

X ⁺ represents the chromosome carrying the normal allele.

If Bob is color-blinded his genotype must be X⁻Y.

He inherited the Y chromosome from his father and the X chromosome from his mother.

The X chromosome must be carrying the recessive allele, X⁻

His mother must be partial color-blinded, having the heter0zyg0us genotype, X⁺X⁻.

His father must have the normal allele, having the genotype X⁺Y.

Cross: father with mother

Parentals) X⁺Y x X⁺X⁻

Gametes) X⁺ Y X⁺ X⁻

Punnett square) X⁺ Y

X⁺ X⁺ X⁺ X⁺Y

X⁻ X⁺X⁻ X⁻Y

F1) 1/4 of the progeny was expected to be normal girls, X⁺ X⁺

1/4 of the progeny was expected to be normal boys, X⁺Y

1/4 of the progeny was expected to be color-blinded girls, X⁺X⁻

1/4 of the progeny was expected to be color-blinded boys, X⁻Y

Bob received the gene for color blindness from his mother.

You can learn more about color-blindness at

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