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A 1060-kg car moving at a speed of 13.0 m/s crashes into an identical car stopped at a light. What is the velocity (in m/s) of the wreckage immediately after the collision, assuming the cars stick together

Respuesta :

Answer:

Speed of the wreck after the collision is 6.5 m/s

Explanation:

When a car hits another and sticks together, the  collision would be totally inelastic.  Since the both the vehicles  locked  together, they have the same final velocity.

Mass of car  [tex]m_{1}=1060 kg[/tex]

Mass of stopped car [tex]m_{2}=1060 kg[/tex]

Initial speed of the car [tex]u_{1}=13 m/s[/tex]

Initial speed  of the stopped car [tex]u_{2}=0 m/s[/tex]

The final velocity of the wreck will be

[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]

since final speed are same, [tex]v_{1}=v_{2}=v[/tex]

[tex]m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v[/tex]

[tex]1060\times 13 +1060 \times 0 =(1060+1060)v\\v=\frac{13780}{2120} \\v=6.5 m/s[/tex]