Calculate the atomic mass of element "X", if it has 2 naturally occurring isotopes with the following masses and natural abundances. X-107 106.90509 amu 51.84% X-109 108.90476 amu 48.16%?

Respuesta :

Answer: The average atomic mass of X element is 107.9 amu

Explanation:

Mass of isotope X-107 = 106.90509 amu

% abundance of isotope 1 = 51.84% = [tex]\frac{51.84}{100}=0.5184[/tex]

Mass of isotope X-109 = 108.90476 amu

% abundance of isotope 2 = 48.16% = [tex]\frac{48.16}{100}=0.4816[/tex]

Formula used for average atomic mass of an element :

[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]

[tex]A=\sum[(106.90509\times 0.5184)+(108.90476\times 0.4816)]][/tex]

[tex]A=107.9amu[/tex]

Therefore, the average atomic mass of X element is 107.9 amu