Answer:
Minimum Allowable diameter for each of the 5 bolts = 0.0394 m = 3.94 cm
Explanation:
Maximum Working Stress = Ultimate Shear Stress/factor of safety
Maximum Working Stress = 280 MPa/3.8 = 73.68 MPa
Working Stress = Applied load/Minimum allowable Area = L/A
Minimum Allowable Area = Applied Load/Maximum Working Stress
A = 450000/73680000 = 0.00611 m²
This area is supplied by 5 bolts, so each bolt supplies A/5 = 0.0061/5 = 0.00122 m²
Cross sectional Area of bolts = πD²/4
0.00122 = πD²/4
D² = 4 × 0.00122/π = 0.00155
D = √0.00155 = 0.0394 m = 3.94 cm
Each of the five bolt can have a minimum diameter of 3.94 cm
Hope this Helps!!!
