Answer:
The coefficient of friction between the block and the surface is μk=0.441
Explanation:
Let
mb = bullet mass = 0.02 kg
vb = bullet speed = 300 m/s
mw = mass of the wood block = 1 kg
d = distance covered by the block plus the bullet = 4 m
u = speed of the bullet plus the block
g = gravity = 9.8 m/s2
μk = coefficient of friction, variable unknown
We will use the following expression to calculate the coefficient of friction:
μk = [tex]\frac{(\frac{mb*vb}{mb+mw})^{2} }{2*g*d}[/tex]
Replacing known values:
μk=[tex]\frac{(\frac{(0.02kg)*(300m/s)}{0.02kg+1kg})^{2} }{2*9.8m/s^{2}*4m }=0.441[/tex]
The coefficient of friction is a dimensionless value
