For her parents' anniversary party, Ashley is considering using one of two venues. A hotel in
Cedarburg will cost $787 for a reservation, plus $17 per person. A restaurant in the same city
will cost $23 per person, in addition to $745 for the reservation. In order to make the best
decision, Ashley figures out how many attendees it would take to have the venues cost the
same amount. How many attendees would that be? What would the total cost be?

Question

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Respuesta :

absor201 absor201 · Answer 1 · 2020-02-14T14:32:47+01:00

It would take 7 attendees for both hotel and restaurant to cost same.

The cost would be $906.

Step-by-step explanation:

Given,

Reservation cost at hotel = $787

Cost per person = $17

Let,

x be the number of attendees

H(x) = 17x+787

Reservation cost at restaurant = $745

Cost per person = $23

R(x) = 23x+745

For same cost;

R(x) = H(x)

[tex]23x+745=17x+787\\23x-17x=787-745\\6x=42[/tex]

Dividing both sides by 6

[tex]\frac{6x}{6}=\frac{42}{6}\\x=7[/tex]

It would take 7 attendees for both hotel and restaurant to cost same.

Putting x=7 in H(x)

H(7) = 17(7) + 787 = 119+787 = $906

Putting x=7 in R(x)

R(7) = 23(7) + 745 = 161 + 745 = $906

The cost would be $906.

Keywords: function, addition

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