Respuesta :
Answer:
2.5 moles of [tex]H_{2}S[/tex] are produced.
Explanation:
Balanced equation: [tex]Na_{2}S+2HCl\rightarrow H_{2}S+2NaCl[/tex]
According to balanced equation-
1 mol of [tex]Na_{2}S[/tex] produces 1 mol of [tex]H_{2}S[/tex]
So, 5.0 moles of [tex]Na_{2}S[/tex] produce 5.0 moles of [tex]H_{2}S[/tex]
2 moles of HCl produce 1 mol of [tex]H_{2}S[/tex]
So, 5.0 moles of HCl produce 2.5 moles of [tex]H_{2}S[/tex]
As least number of moles of [tex]H_{2}S[/tex] are produced from HCl therefore HCl is the limiting reagent.
Hence 2.5 moles of [tex]H_{2}S[/tex] are produced.
Moles of hydrogen sulfide (H₂S) are produced are 2.5 moles.
Given:
Moles of hydrochloric acid= 5.0 mol
Balanced equation:
[tex]2HCl+ Na_2S----> H_2S+ 2NaCl[/tex]
From the given equation,
- 1 mol of Na₂S produces 1 mol of H₂S
So, 5.0 moles of Na₂S produces 5.0 moles of H₂S
- 2 moles of HCl produce 1 mol of H₂S
So, 5.0 moles of HCl produce 2.5 moles of H₂S
HCl is the limiting reagent since, least number of moles of H₂S are produced.
Thus, 2.5 moles of H₂S are produced.
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