Answer:
Tangential speed=5.4 m/s
Radial acceleration=[tex]88.6m/s^2[/tex]
Explanation:
We are given that
Angular speed=2.59 rev/s
We know that
1 revolution=[tex]2\pi rad[/tex]
2.59 rev=[tex]2\pi\times 2.59=5.18\pi=5.18\times 3.14=16.27 rad/s[/tex]
By using [tex]\pi=3.14[/tex]
Angular velocity=[tex]\omega=16.27rad/s[/tex]
Distance from axis=r=0.329 m
Tangential speed=[tex]r\omega=16.27\times 0.329=5.4m/s[/tex]
Radial acceleration=[tex]\frac{v^2}{r}[/tex]
Radial acceleration=[tex]\frac{(5.4)^2}{0.329}=88.6m/s^2[/tex]